(b) time of fall of the body? It is applied to all the body present in universe It is constant of proportionality in Newton’s universal law of gravitation. The Following Section consists of Gravitation Questions on Physics. Page No: 134. Why does a body reach the ground quicker at poles than at the equator when dropped from the same height? Question 5. Question 19. (i) Original weight = \(\frac{G M m}{r^{2}}\), where M is the mass of the earth. At what place on the earth’s surface is the weight of a body minimum? Question 4. ... plz answer this questions. Practice questions The gravitational force between […] Fp = \(\frac{G \times M_{e} \times m_{1}}{R^{2}}\) …..(1) A student thought that two bricks tied together would fall faster than a single one under the action of gravity. OTP has been sent to your mobile number and is valid for one hour Give reasons. Previous: Contents: Next: Question 1. Why is ‘G’ called the universal gravitational constant? u = 0 ms-1, h = 49 m, % Variation in the weight of a body = % Change in g = 0.7%. The earth is acted upon by gravitation of sun, even though it does not fall into the sun. Question 7: Law of gravitation gives the gravitational force between (a) the earth and a point mass only or F = G × \(\frac{m_{1} m_{2}}{r^{2}}\) ……..(3) or, v = \(\sqrt{800}\) Question 1. The weight of the body on the moon is about one-sixth of its weight on the earth. Here, s = 100 m, u = 0 Question 15. [NCERT Exemplar] Both stones will take the same time to reach the ground because the two stones fall from the same height. Here, initial velocity, u = 0 [NCERT Exemplar] What keeps the moon in uniform circular motion around the earth? Weight is not a constant quantity. The solved question papers from chapter 08 Gravitation have all type of questions may be asked in annual exams such as VSA very short answer type questions, SA short answer type questions, LA long answer type questions, VBA value based questions and HOTS higher order thinking skill based questions. Answer: Calculate the average density of the earth in terms of g, G and R. Question 5. Acceleration due to gravity is the acceleration acquired by a body due to the earth’s gravitational pull on it. As the body falls back to the earth with the same velocity it was thrown vertically upwards. The moon will begin to move in a straight line in the direction in which it was moving at that instant because the circular motion of moon is due to centripetal force provided by the gravitational force of the earth. Identical packets are dropped from two aeroplanes—one above the equator and other above the north pole, both at height h. Assuming all conditions to be identical, will those packets take same time to reach the surface of earth? Answer: If a body of mass m is placed on the surface of moon, then weight of the body on the moon is What is the source of centripetal force that a planet requires to revolve around the sun? Answer: Find the position of that point. (a) In which direction is the ball moving at point C? Answer: They both hit the ground at the same time. Answer: = 0 – (0.5)2 = 2 × (-9.8) × h or t = \(\frac{0.5}{9.8}\) = 0.05 s. Question 11. So, the earth does not fall into the sun. Is weight a force? [NCERT Exemplar] F ∝ \(\frac{m_{1} \times m_{2}}{r^{2}}\) Define acceleration due to gravity. Question 1. Answer: v = u + gt1 It’s what keeps us safe on the ground, as opposed to floating up through the air. Initial velocity, u = 0 Answer: The ‘G’ is a universal constant, i.e., its value is the same (i.e. Therefore, the packets fall slowly at equator in comparison to the poles. When hypothetically M becomes 4 M and R becomes \(\frac{R}{2}\). i.e., First stone would take 3.16 s to reach the ground. 1. 0 = 0.5 – 9.8t TopperLearning’s Experts and Students has answered all of Gravitation of MAHARASHTRA Class 10 Physics questions in detail. Derive an expression for acceleration due to gravity in terms of mass of the earth (M) and universal gravitational constant (G). The accepted value of G is 6.67x 1CT-11 Nm 2 kg-2. Question 1. Answer: W = \(\frac{G M m}{(2 r)^{2}}\) = \(\frac{G M m}{4 r^{2}}=\frac{W}{4}\) Let P and Q be the two bodies, Free PDF Download - Best collection of CBSE topper Notes, Important Questions, Sample papers and NCERT Solutions for CBSE Class 9 Physics Gravitation. Any four phenomena that the force of gravity is 1.67 ms-2 radius of the body appears be! Places on the moon in Newton ’ s universal law of gravitation was able to explain,... Equator is 6378 km fall under the action of gravity two objects with equal force,,. 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